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Mathias Agopian4b8a3d82007-08-23 03:16:02 -07001/*
2 * Copyright (C) 2007 Google Inc.
3 *
4 * Licensed under the Apache License, Version 2.0 (the "License");
5 * you may not use this file except in compliance with the License.
6 * You may obtain a copy of the License at
7 *
8 * http://www.apache.org/licenses/LICENSE-2.0
9 *
10 * Unless required by applicable law or agreed to in writing, software
11 * distributed under the License is distributed on an "AS IS" BASIS,
12 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
13 * See the License for the specific language governing permissions and
14 * limitations under the License.
15 */
16
17#include <math.h>
18#include <stdio.h>
19
20static double sinc(double x) {
21 if (fabs(x) == 0.0f) return 1.0f;
22 return sin(x) / x;
23}
24
25static double sqr(double x) {
26 return x*x;
27}
28
29static double I0(double x) {
30 // from the Numerical Recipes in C p. 237
31 double ax,ans,y;
32 ax=fabs(x);
33 if (ax < 3.75) {
34 y=x/3.75;
35 y*=y;
36 ans=1.0+y*(3.5156229+y*(3.0899424+y*(1.2067492
37 +y*(0.2659732+y*(0.360768e-1+y*0.45813e-2)))));
38 } else {
39 y=3.75/ax;
40 ans=(exp(ax)/sqrt(ax))*(0.39894228+y*(0.1328592e-1
41 +y*(0.225319e-2+y*(-0.157565e-2+y*(0.916281e-2
42 +y*(-0.2057706e-1+y*(0.2635537e-1+y*(-0.1647633e-1
43 +y*0.392377e-2))))))));
44 }
45 return ans;
46}
47
48static double kaiser(int k, int N, double alpha) {
49 if (k < 0 || k > N)
50 return 0;
51 return I0(M_PI*alpha * sqrt(1.0 - sqr((2.0*k)/N - 1.0))) / I0(M_PI*alpha);
52}
53
54int main(int argc, char** argv)
55{
56 // nc is the number of bits to store the coefficients
57 int nc = 16;
58
59 // ni is the minimum number of bits needed for interpolation
60 // (not used for generating the coefficients)
61 const int ni = nc / 2;
62
63 // nzc is the number of zero-crossing on one half of the filter
64 int nzc = 12;
65
66 // alpha parameter of the kaiser window
67 // Larger numbers reduce ripples in the rejection band but increase
68 // the width of the transition band. In reality there doesn't seem to be
69 // a good reason to choose a big number because of the limited range
70 // of our coefficients (16 bits).
71 double alpha = 3.0;
72
73 // cut off frequency ratio Fc/Fs
74 double Fcr = 20000.0 / 44100.0;
75
76 // 2^nz is the number coefficients per zero-crossing
77 // (int theory this should be 1<<(nc/2))
78 const int nz = 4;
79
80 // total number of coefficients
81 const int N = (1 << 4) * nzc;
82
83 // generate the right half of the filter
84
85 printf("const int32_t RESAMPLE_FIR_SIZE = %d;\n", N);
86 printf("const int32_t RESAMPLE_FIR_NUM_COEF = %d;\n", nzc);
87 printf("const int32_t RESAMPLE_FIR_COEF_BITS = %d;\n", nc);
88 printf("const int32_t RESAMPLE_FIR_LERP_FRAC_BITS = %d;\n", ni);
89 printf("const int32_t RESAMPLE_FIR_LERP_INT_BITS = %d;\n", nz);
90 printf("\n");
91 printf("static int16_t resampleFIR[%d] = {", N);
92 for (int i=0 ; i<N ; i++)
93 {
94 double x = (2.0 * M_PI * i * Fcr) / (1 << 4);
95 double y = kaiser(i+N, 2*N, alpha) * sinc(x);
96
97 int yi = floor(y * (1<<(nc-1)) + 0.5);
98 if (yi >= (1<<(nc-1))) yi = (1<<(nc-1))-1;
99
100 //printf("%6d\n", yi);
101
102 if ((i % (1 << 4)) == 0) printf("\n ");
103 printf("0x%04x, ", yi & 0xFFFF);
104 }
105 printf("\n};\n");
106
107 return 0;
108 }
109