patch 8.2.1081: Lua: cannot use table.insert() and table.remove()
Problem: Lua: cannot use table.insert() and table.remove().
Solution: Add the list functions. (Prabir Shrestha, closes #6353)
diff --git a/runtime/doc/if_lua.txt b/runtime/doc/if_lua.txt
index f32be7c..2141796 100644
--- a/runtime/doc/if_lua.txt
+++ b/runtime/doc/if_lua.txt
@@ -227,8 +227,17 @@
in Vim.
o "l[k]" returns the k-th item in "l"; "l" is one-indexed, as in Lua.
To modify the k-th item, simply do "l[k] = newitem"; in
- particular, "l[k] = nil" removes the k-th item from "l".
+ particular, "l[k] = nil" removes the k-th item from "l". Item can
+ be added to the end of the list by "l[#l + 1] = newitem"
o "l()" returns an iterator for "l".
+ o "table.insert(l, newitem)" inserts an item at the end of the list.
+ (only Lua 5.3 and later)
+ o "table.insert(l, position, newitem)" inserts an item at the
+ specified position. "position" is one-indexed. (only Lua 5.3 and
+ later)
+ o "table.remove(l, position)" removes an item at the specified
+ position. "position" is one-indexed.
+
Methods
-------
@@ -246,8 +255,11 @@
:lua l[1] = nil -- remove first item
:lua l:insert(true, 1)
:lua print(l, #l, l[1], l[2])
+ :lua l[#l + 1] = 'value'
+ :lua table.insert(l, 100)
+ :lua table.insert(l, 2, 200)
+ :lua table.remove(l, 1)
:lua for item in l() do print(item) end
-<
==============================================================================
4. Dict userdata *lua-dict*