patch 9.0.0957: tests fail without the terminal feature
Problem: Tests fail without the terminal feature.
Solution: Move functions to another utility script.
diff --git a/src/testdir/view_util.vim b/src/testdir/view_util.vim
index a4d0e56..a0c1781 100644
--- a/src/testdir/view_util.vim
+++ b/src/testdir/view_util.vim
@@ -62,3 +62,43 @@
bw!
redraw!
endfunc
+
+
+" When using RunVimInTerminal() we expect modifyOtherKeys level 2 to be enabled
+" automatically. The key + modifier Escape codes must then use the
+" modifyOtherKeys encoding. They are recognized anyway, thus it's safer to use
+" than the raw code.
+
+" Return the modifyOtherKeys level 2 encoding for "key" with "modifier"
+" (number value, e.g. CTRL is 5).
+func GetEscCodeCSI27(key, modifier)
+ let key = printf("%d", char2nr(a:key))
+ let mod = printf("%d", a:modifier)
+ return "\<Esc>[27;" .. mod .. ';' .. key .. '~'
+endfunc
+
+" Return the modifyOtherKeys level 2 encoding for "key" with "modifier"
+" (character value, e.g. CTRL is "C").
+func GetEscCodeWithModifier(modifier, key)
+ let modifier = get({'C': 5}, a:modifier, '')
+ if modifier == ''
+ echoerr 'Unknown modifier: ' .. a:modifier
+ endif
+ return GetEscCodeCSI27(a:key, modifier)
+endfunc
+
+" Return the kitty keyboard protocol encoding for "key" with "modifier"
+" (number value, e.g. CTRL is 5).
+func GetEscCodeCSIu(key, modifier)
+ let key = printf("%d", char2nr(a:key))
+ let mod = printf("%d", a:modifier)
+ return "\<Esc>[" .. key .. ';' .. mod .. 'u'
+endfunc
+
+" Return the kitty keyboard protocol encoding for "key" without a modifier.
+" Used for the Escape key.
+func GetEscCodeCSIuWithoutModifier(key)
+ let key = printf("%d", char2nr(a:key))
+ return "\<Esc>[" .. key .. 'u'
+endfunc
+